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John D. Cook

Second solutions What is the quality of software that AI writes? Junk solutions Ultraspherical Numerical (in)stability of recurrece relations Three-term recurrences von Mises probability distribution | von Mises-Fisher What exactly is modified about a modified Bessel function? Why special function terminology is arcane Coming soon How would you know whether an ancient culture had zero? AI-generated ASCII diagrams Big little hexagon The imbalance theorem Mean distance to the sun Proportion of 1s in a Hadamard matrix Probability of correcting errors Compressing a Hadamard matrix Hadamard Codes and Sphere Packing How NASA’s Mariner 9 probe encoded images Constructing Hadamard matrices Cryptic but consistent Dogs and fat tails Manually unbreakable cryptography Learning from historical mistakes Inverse differential equations DNA and Bessel functions Simple range reduction algorithm by Cody and Waite Corrupted apostrophes How not to calculate cosine
The difference orbit inclination makes
John · 2026-08-23 · via John D. Cook

Suppose you wanted to find the distance between Earth and Mars over time. To first approximation, both planets orbit the sun in elliptic orbits in the same plane.

If you wanted to be more accurate, you’d need to take into account the fact that the orbit of Mars is tilted about 1.85° relative to the Earth’s orbit. How much difference does that make?

To simplify things, let’s assume the Earth orbits the sun in a circle of radius 1 and Mars orbits the sun in a circle of radius 1.5. The distance between Earth and Mars over time would be basically sinusoidal.

How much does inclination contribute to this distance? In other words, what is the difference between the distance accounting for the inclination of Mars’ orbit and the distance if we assume the two orbits are in the same plane?

This plot gives the answer.

The effect is not large, about three orders of magnitude smaller than the main effect, but it’s interesting how erratic it is.

The plots were made with the following code.

from numpy import *

R = 1.5
T = R**1.5 # Kepler's third law

def f(t, theta):
    return sqrt(
        (cos(t) - R*cos(t/T)*cos(theta))**2 +
        (sin(t) - R*sin(t/T))**2 +
        (R*sin(theta)*cos(t/T))**2
    )

The first plot graphs f(t, θ) and the second graphs f(t, θ) − f(t, 0).