惯性聚合 高效追踪和阅读你感兴趣的博客、新闻、科技资讯
阅读原文 在惯性聚合中打开

推荐订阅源

V
Visual Studio Blog
Stack Overflow Blog
Stack Overflow Blog
G
Google Developers Blog
Microsoft Azure Blog
Microsoft Azure Blog
Engineering at Meta
Engineering at Meta
L
LangChain Blog
T
The Blog of Author Tim Ferriss
J
Java Code Geeks
Y
Y Combinator Blog
月光博客
月光博客
雷峰网
雷峰网
OSCHINA 社区最新新闻
OSCHINA 社区最新新闻
F
Fortinet All Blogs
A
About on SuperTechFans
让小产品的独立变现更简单 - ezindie.com
让小产品的独立变现更简单 - ezindie.com
P
Proofpoint News Feed
小众软件
小众软件
H
Help Net Security
Last Week in AI
Last Week in AI
B
Blog RSS Feed
宝玉的分享
宝玉的分享
N
Netflix TechBlog - Medium
博客园 - 叶小钗
The GitHub Blog
The GitHub Blog

博客园 - 北叶青藤

2096. Step-By-Step Directions From a Binary Tree Node to Another Find path from root to a target node in Binary Tree When Dijkstra Algorithm Should be Use? 1188. Design Bounded Blocking Queue 1115. Print FooBar Alternately 1114. Print in Order 1242. Web Crawler Multithreaded Python Multi-threading bot ip Log Rate Limiter Same Word of HTML Labels Most Frequent Call Chain remove prefix in a words list 1102. Path With Maximum Minimum Value Property Booking Optimizer minimum number 755. Pour Water Keyword Tagging in Reviews with Overlapping Matches Retryer Function Implementation 1125. Smallest Sufficient Team Print the terrain Split stay Task scheduling problem 滑雪问题 845. Longest Mountain in Array 723. Candy Crush 1539. Kth Missing Positive Number 1650. Lowest Common Ancestor of a Binary Tree III 424. Longest Repeating Character Replacement 551. Student Attendance Record I
843. Guess the Word
北叶青藤 · 2021-07-06 · via 博客园 - 北叶青藤

his is an interactive problem.

You are given an array of unique strings wordlist where wordlist[i] is 6 letters long, and one word in this list is chosen as secret.

You may call Master.guess(word) to guess a word. The guessed word should have type string and must be from the original list with 6 lowercase letters.

This function returns an integer type, representing the number of exact matches (value and position) of your guess to the secret word. Also, if your guess is not in the given wordlist, it will return -1 instead.

For each test case, you have exactly 10 guesses to guess the word. At the end of any number of calls, if you have made 10 or fewer calls to Master.guess and at least one of these guesses was secret, then you pass the test case.

Example 1:

Input: secret = "acckzz", wordlist = ["acckzz","ccbazz","eiowzz","abcczz"], numguesses = 10
Output: You guessed the secret word correctly.
Explanation:
master.guess("aaaaaa") returns -1, because "aaaaaa" is not in wordlist.
master.guess("acckzz") returns 6, because "acckzz" is secret and has all 6 matches.
master.guess("ccbazz") returns 3, because "ccbazz" has 3 matches.
master.guess("eiowzz") returns 2, because "eiowzz" has 2 matches.
master.guess("abcczz") returns 4, because "abcczz" has 4 matches.
We made 5 calls to master.guess and one of them was the secret, so we pass the test case.

Example 2:

Input: secret = "hamada", wordlist = ["hamada","khaled"], numguesses = 10
Output: You guessed the secret word correctly.
 1 /**
 2  * // This is the Master's API interface.
 3  * // You should not implement it, or speculate about its implementation
 4  * interface Master {
 5  *     public int guess(String word) {}
 6  * }
 7  */
 8 class Solution {
 9     public void findSecretWord(String[] wordlist, Master master) {
10         Random random = new Random();
11         for(int i = 0, matches = 0; i < 10 && matches != 6; i ++){
12             String guess = wordlist[random.nextInt(wordlist.length)];
13             matches = master.guess(guess);
14             List<String> candidates = new ArrayList<>();
15             for(String word: wordlist){
16                 if(matches == getMatches(guess, word)){
17                     candidates.add(word);
18                 }
19             }
20             
21             wordlist = candidates.toArray(new String[0]);
22         }
23     }
24     
25     private int getMatches(String word1, String word2){
26         int matches = 0;
27         for(int i = 0; i < word1.length(); i ++){
28             if(word1.charAt(i) == word2.charAt(i)){
29                 matches ++;
30             }
31         }
32         
33         return matches;
34     }
35 }