Let $0 \leq s \leq 1$, and let $\mathbb{P} := \{(t,t^{2}) \in \mathbb{R}^{2} : t \in [-1,1]\}$. If $K \subset \mathbb{P}$ is a closed set with $\dim_{\mathrm{H}} K = s$, it is not hard to see that $\dim_{\mathrm{H}} (K + K) \geq 2s$. The main corollary of the paper states that if $0 < s < 1$, then adding $K$ once more makes the sum slightly larger: $$\dim_{\mathrm{H}} (K + K + K) \geq 2s + ε, $$ where $ε= ε(s) > 0$. This information is deduced from an $L^{6}$ bound for the Fourier transforms of Frostman measures on $\mathbb{P}$. If $0 < s < 1$, and $μ$ is a Borel measure on $\mathbb{P}$ satisfying $μ(B(x,r)) \leq r^{s}$ for all $x \in \mathbb{P}$ and $r > 0$, then there exists $ε= ε(s) > 0$ such that $$ \|\hatμ\|_{L^{6}(B(R))}^{6} \leq R^{2 - (2s + ε)} $$ for all sufficiently large $R \geq 1$. The proof is based on a reduction to a $δ$-discretised point-circle incidence problem, and eventually to the $(s,2s)$-Furstenberg set problem.