![]() |
func_get_args
(PHP 4, PHP 5)
func_get_args -- Returns an array comprising a function's argument list Description
array func_get_args ( void ) Returns an array in which each element is a copy of the corresponding member of the current user-defined function's argument list. func_get_args() will generate a warning if called from outside of a function definition. This function cannot be used directly as a function parameter. Instead, its result may be assigned to a variable, which can then be passed to the function.
注: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.
注: 因为本函数依赖于当前域来决定参数细节，因此不能用作函数参数。如果必须要传递这个值，将结果赋给一个变量，然后传递该变量。
|
1 <?php
2 function foo()
3 {
4 $numargs = func_num_args();
5 echo "Number of arguments: $numargs<br />\n";
6 if ($numargs >= 2) {
7 echo "Second argument is: " . func_get_arg(1) . "<br />\n";
8 }
9 $arg_list = func_get_args();
10 for ($i = 0; $i < $numargs; $i++) {
11 echo "Argument $i is: " . $arg_list[$i] . "<br />\n";
12 }
13 }
14
15 foo(1, 2, 3);
16 ?>
http://www.kuqin.com/php5_doc/function.func-get-args.html
