推荐订阅源

ORACLE中表 test(a,b,c)有记录如下：
A                 B                      C
1                 XXX                   01
2                 YYY                   01
3                 KKK                   02
4                 III                   02
。。。。
把C相同的B根据序号A串联起来，即得到这样的结果
 B           C
XXXYYY       01
KKKIII       02

create table test(a int,b varchar2(100),c varchar2(100));
insert into test
select 1,'XXX','01' from dual union all 
select 2,'YYY','01' from dual union all
select 3,'KKK','02' from dual union all
select 4,'III','02' from dual;

select c,replace(substr(max(sys_connect_by_path(b, '|')), 2),'|','') b
from (select b, c, row_number() over(partition by c order by 1) rn
from test)
start with rn = 1
connect by rn - 1 = prior rn and c = prior c
group by c;