In JavaScript, single quotes('') and double quotes("") are interchangeable. With ES6, we now even have backticks(``) for template literals. When you want to write a quick script to find all the strings without introducing a heavy parser, you may think about using RegExp. For example, you can have:

/['"`](.*?)['"`]/g

It works for most of the case, but not for mixed quotes:

'const a = "Hi, I\'m Anthony"'.match(/['"`](.*)['"`]/)[1] // "Hi, I"

You have to make sure the starting quote and ending quote are the same type. Initially I thought it was impossible to do it in RegExp, or we have to do like this:

/'(.*?)'|"(.*?)"|`(.*?)`/g

That’s definitely a bad idea as it makes you duplicated your notations. Until I found this solution:

/(['"`])(.*?)\1/g

\1 is a Backreferences to your first group, similarly you can have \2 for the second group 2 and \3 for the third, you got the idea. This is exactly what I need! Take it a bit further, to exclude the backslash escaping, now we can have a much reliable RegExp for extracting quoted texts from any code.

/(["'`])((?:\\\1|(?:(?!\1)|\n|\r).)*?)\1/g

You can find it running in action on my vite-plugin-windicss.