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博客园 - Dabay

[Leetcode][Python]56: Merge Intervals [Leetcode][Python]54: Spiral Matrix [Leetcode][Python]53: Maximum Subarray [Leetcode][Python]52: N-Queens II [Leetcode][Python]51: N-Queens [Leetcode][Python]50: Pow(x, n) [Leetcode][Python]49: Anagrams [Leetcode][Python]48: Rotate Image [Leetcode][Python]47: Permutations II [Leetcode][Python]46: Permutations [Leetcode][Python]45: Jump Game II [Leetcode][Python]44:Wildcard Matching [Leetcode][Python]43: Multiply Strings [Leetcode][Python]42: Trapping Rain Water [Leetcode][Python]41: First Missing Positive [Leetcode][Python]40: Combination Sum II [Leetcode][Python]39: Combination Sum [Leetcode][Python]19: Remove Nth Node From End of List [Leetcode][Python]37: Sudoku Solver
[Leetcode][Python]55: Jump Game
Dabay · 2015-04-07 · via 博客园 - Dabay
# -*- coding: utf8 -*-
'''
__author__ = 'dabay.wang@gmail.com'

55: Jump Game
https://leetcode.com/problems/jump-game/

Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Determine if you are able to reach the last index.
For example:
A = [2,3,1,1,4], return true.
A = [3,2,1,0,4], return false.

=== Comments by Dabay===
每次计算能到达的新范围。
如果新的范围超越了len(A)-1就范围True.
'''

class Solution:
# @param A, a list of integers
# @return a boolean
def canJump(self, A):
if len(A) <= 1:
return True
start = 0
end = start + A[start]
while end >= start:
if end >= len(A) - 1:
return True
new_end = end
for i in xrange(start, end+1):
new_end = max(new_end, i + A[i])
start, end = end+1, new_end
else:
return False

def main():
sol = Solution()
A = [1,1,1,0]
print sol.canJump(A)

if __name__ == "__main__":
import time
start = time.clock()
main()
print "%s sec" % (time.clock() - start)