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SQL 2005中，通常会用到在SQL参数中传递表结构，最简单的办法是利用XML转换为table

代码

DECLARE    @h INT,
    @XML VARCHAR(8000),
    @2k5 XMLSELECT    @XML =    '
            <jrt>
                <item>
                    <id>11</id>
                    <name>CS Tester</name>
                    <company>EEE</company>
                    <phone>555-555-1234</phone>
                </item>
                <item>
                    <id>22</id>
                    <name>CS Tester</name>
                    <company>EEE</company>
                    <phone>555-555-1234</phone>
                </item>
            </jrt>
        ',
    @2k5 = @XMLSELECT    T.c.query('id').value('.[1]', 'varchar(100)') as id,
        T.c.query('name').value('.[1]', 'varchar(50)') as name,
        T.c.query('company').value('.[1]', 'varchar(50)') as company,
        T.c.query('phone').value('.[1]', 'nvarchar(50)') as phone
FROM    @2k5.nodes('/jrt/item') AS T(c)

 结果是：

id         name       company    phone
---------- ---------- ---------- ----------
11         CS Tester  EEE        555-555-12
22         CS Tester  EEE        555-555-12