























-- This script converts string-based IP addresses to their numeric
equivalents so that it is easy to do arithmatic on them such as find an
IP address that is within a range.
--
-- NOTE: This function calls the split function which is included in the po
IF exists (SELECT * from dbo.sysobjects
WHERE id = object_id(N'[dbo].[IPStringToNumber]')
AND OBJECTPROPERTY(id, N'IsScalarFunction') = 1)
DROP FUNCTION [dbo].[IPStringToNumber]
GO
CREATE FUNCTION dbo.IPStringToNumber( @vcIPAddress varchar(15))
/**************************************************************************
DESCRIPTION: Returns Numeric IP, otherwise returns null
PARAMETERS:
@vcIPAddress - The string containing a valid IP
RETURNS: IP converted to bigint or null if not a valid IP
USAGE: SELECT dbo.IPStringToNumber( '10.255.255.255')
AUTHOR: Karen Gayda
DATE: 06/11/2003
MODIFICATION HISTORY:
WHO DATE DESCRIPTION
---
----------
---------------------------------------------------
***************************************************************************/
RETURNS bigint
AS
BEGIN
DECLARE
@biOctetA bigint,
@biOctetB bigint,
@biOctetC bigint,
@biOctetD bigint,
@biIP bigint
DECLARE @tblArray TABLE
(
OctetID
smallint,
--Array index
Octet bigint
--Array element
contents
)
--split the IP string and insert each octet into a table row
INSERT INTO @tblArray
SELECT ElementID, Convert(bigint,Element) FROM dbo.Split(@vcIPAddress, '.')
--check that there are four octets and that they are within valid ranges
IF (SELECT COUNT(*) FROM @tblArray WHERE Octet BETWEEN 0 AND 255) = 4
BEGIN
SET @biOctetA = (SELECT (Octet * 256 * 256 * 256) FROM @tblArray WHERE OctetID = 1)
SET @biOctetB = (SELECT (Octet * 256 * 256 ) FROM @tblArray WHERE OctetID = 2)
SET @biOctetC = (SELECT (Octet * 256 ) FROM @tblArray WHERE OctetID = 3)
SET @biOctetD = (SELECT (Octet) FROM @tblArray WHERE OctetID = 4)
SET @biIP = @biOctetA + @biOctetB + @biOctetC + @biOctetD
END
RETURN(@biIP)
END
IF exists (SELECT * from dbo.sysobjects
WHERE id = object_id(N'[dbo].[Split]')
AND OBJECTPROPERTY(id, N'IsTableFunction') = 1)
DROP FUNCTION [dbo].[Split]
GO
GO
CREATE FUNCTION dbo.Split
(
@vcDelimitedString varchar(8000),
@vcDelimiter varchar(100)
)
/**************************************************************************
DESCRIPTION: Accepts a delimited string and splits it at the specified
delimiter points. Returns the individual items as a table data
type with the ElementID field as the array index and the Element
field as the data
PARAMETERS:
@vcDelimitedString - The string to be split
@vcDelimiter
- String containing the delimiter
where
delimited string should be split
RETURNS:
Table data type containing array of strings that were split with
the delimiters removed from the source string
USAGE:
SELECT ElementID, Element FROM Split('11111,22222,3333', ',') ORDER BY ElementID
AUTHOR: Karen Gayda
DATE: 05/31/2001
MODIFICATION HISTORY:
WHO DATE DESCRIPTION
---
----------
---------------------------------------------------
***************************************************************************/
RETURNS @tblArray TABLE
(
ElementID smallint IDENTITY(1,1), --Array index
Element
varchar(1000)
--Array element contents
)
AS
BEGIN
DECLARE
@siIndex
smallint,
@siStart
smallint,
@siDelSize
smallint
SET @siDelSize = LEN(@vcDelimiter)
--loop through source string and add elements to destination table array
WHILE LEN(@vcDelimitedString) > 0
BEGIN
SET @siIndex = CHARINDEX(@vcDelimiter, @vcDelimitedString)
IF @siIndex = 0
BEGIN
INSERT INTO @tblArray VALUES(@vcDelimitedString)
BREAK
END
ELSE
BEGIN
INSERT INTO
@tblArray VALUES(SUBSTRING(@vcDelimitedString, 1,@siIndex - 1))
SET @siStart = @siIndex + @siDelSize
SET
@vcDelimitedString = SUBSTRING(@vcDelimitedString, @siStart ,
LEN(@vcDelimitedString) - @siStart + 1)
END
END
RETURN
END
GO
此内容由惯性聚合(RSS阅读器)自动聚合整理,仅供阅读参考。 原文来自 — 版权归原作者所有。