










Given a text file file.txt, print just the 10th line of the file.
Example:
Assume that file.txt has the following content:
Line 1
Line 2
Line 3
Line 4
Line 5
Line 6
Line 7
Line 8
Line 9
Line 10
Your script should output the tenth line, which is:
Line 10
Note:
tail -n+10 file.txt | head -1
sed '10p' file.txt
awk 'NR==10' file.txt
no=0
while IFS= read -r line
do
((no=$no+1))
if [[ $no -eq 10 ]]
then
echo $line
break
fi
done < "file.txt"
此内容由惯性聚合(RSS阅读器)自动聚合整理,仅供阅读参考。 原文来自 — 版权归原作者所有。