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cs.IT updates on arXiv.org

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A spin glass model for reconstructing nonlinearly encrypt...
Yan V Fyodorov · 2018-05-18 · via cs.IT updates on arXiv.org

An encryption of a signal ${\bf s}\in\mathbb{R^N}$ is a random mapping ${\bf s}\mapsto \textbf{y}=(y_1,\ldots,y_M)^T\in \mathbb{R}^M$ which can be corrupted by an additive noise. Given the Encryption Redundancy Parameter (ERP) $μ=M/N\ge 1$, the signal strength parameter $R=\sqrt{\sum_i s_i^2/N}$, and the ('bare') noise-to-signal ratio (NSR) $γ\ge 0$, we consider the problem of reconstructing ${\bf s}$ from its corrupted image by a Least Square Scheme for a certain class of random Gaussian mappings. The problem is equivalent to finding the configuration of minimal energy in a certain version of spherical spin glass model, with squared Gaussian-distributed random potential. We use the Parisi replica symmetry breaking scheme to evaluate the mean overlap $p_{\infty}\in [0,1]$ between the original signal and its recovered image (known as 'estimator') as $N\to \infty$, which is a measure of the quality of the signal reconstruction. We explicitly analyze the general case of linear-quadratic family of random mappings and discuss the full $p_{\infty} (γ)$ curve. When nonlinearity exceeds a certain threshold but redundancy is not yet too big, the replica symmetric solution is necessarily broken in some interval of NSR. We show that encryptions with a nonvanishing linear component permit reconstructions with $p_{\infty}>0$ for any $μ>1$ and any $γ<\infty$, with $p_{\infty}\sim γ^{-1/2}$ as $γ\to \infty$. In contrast, for the case of purely quadratic nonlinearity, for any ERP $μ>1$ there exists a threshold NSR value $γ_c(μ)$ such that $p_{\infty}=0$ for $γ>γ_c(μ)$ making the reconstruction impossible. The behaviour close to the threshold is given by $p_{\infty}\sim (γ_c-γ)^{3/4}$ and is controlled by the replica symmetry breaking mechanism.