Let $σ$ be a non-atomic, infinite Radon measure on $\mathbb R^d$, for example, $dσ(x)=z\,dx$ where $z>0$. We consider a system of freely independent particles $x_1,\dots,x_N$ in a bounded set $Λ\subset\mathbb R^d$, where each particle $x_i$ has distribution $\frac1{σ(Λ)}\,σ$ on $Λ$ and the number of particles, $N$, is random and has Poisson distribution with parameter $σ(Λ)$. If the particles were classically independent rather than freely independent, this particle system would be the restriction to $Λ$ of the Poisson point process on $\mathbb R^d$ with intensity measure $σ$. In the case of free independence, this particle system is not the restriction of the free Poisson process on $\mathbb R^d$ with intensity measure $σ$. Nevertheless, we prove that this is true in an approximative sense: if bounded sets $Λ^{(n)}$ ($n\in\mathbb N$) are such that $Λ^{(1)}\subsetΛ^{(2)}\subsetΛ^{(3)}\subset\dotsm$ and $\bigcup_{n=1}^\infty Λ^{(n)}=\mathbb R^d$, then the corresponding particle system in $Λ^{(n)}$ converges (as $n\to\infty$) to the free Poisson process on $\mathbb R^d$ with intensity measure $σ$. We also prove the following $N/V$-limit: Let $N^{(n)}$ be a determinstic sequence of natural numbers such that $\lim_{n\to\infty}N^{(n)}/σ(Λ^{(n)})=1$. Then the system of $N^{(n)}$ freely independent particles in $Λ^{(n)}$ converges (as $n\to\infty$) to the free Poisson process. We finally extend these results to the case of a free Lévy white noise (in particular, a free Lévy process) without free Gaussian part.