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In this paper, we investigate the other extremal question: how low can the ranks of such matrices be? We work with sequences $\mathbf{a}$ that take only two distinct values, so the rank of any such $n \times n$ matrix is at least $n/2$. First, we show that the rank of any such matrix depends on whether an associated bipartite graph has certain eigenvalues of high multiplicity. Using this, we show that if $f$ is linear, then there are $n \times n$ real matrices $M_{T}(f; \mathbf{a})$ of rank at most $\frac{n}{2} + O(1)$. For rational matrices, we show that for each $\varepsilon > 0$ we can find a sequence $\mathbf{a}(\varepsilon)$ for which there are $n \times n$ matrices $M_{T}(f; \mathbf{a}(\varepsilon))$ of rank at most $(\frac{1}{2} + \varepsilon)n + O(1)$. These matrices are constructed from symmetric designs, and we also use them to produce bisection-closed families of size greater than $\lfloor 3n/2 \rfloor - 2$ for $n \leq 15$, which improves the previously best known bound (cf. Balachandran et al., Electron J. Combin. 26 (2019), #P2.40).
From: Brahadeesh Sankarnarayanan [view email]
[v1]
Thu, 25 Jan 2024 08:47:33 UTC (14 KB)
[v2]
Thu, 25 Apr 2024 07:33:22 UTC (14 KB)
[v3]
Mon, 29 Apr 2024 15:48:32 UTC (13 KB)
[v4]
Wed, 4 Jun 2025 13:45:08 UTC (14 KB)
[v5]
Sat, 4 Jul 2026 16:30:53 UTC (14 KB)
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