The {\em square} of a graph $G$, denoted $G^2$, has the same vertex set as $G$ and has an edge between two vertices if the distance between them in $G$ is at most $2$. In general, $Δ(G) + 1 \leq χ(G^2) \leq Δ(G)^2 +1$ for every graph $G$. Charpentier [1] asked whether $χ(G^2) \leq 2 Δ(G)$ if $mad(G) < 4$. But Hocquard, Kim, and Pierron [6] answered his question negatively. For every even value of $Δ(G)$, they constructed a 2-degenerate graph $G$ such that $ω(G^2) = \frac{5}{2} Δ(G)$. Note that if $G$ is a 2-degenerate graph, then $mad(G) < 4$. Thus, we have that \[ {\displaystyle \frac{5}{2} Δ(G) \leq \max \{χ(G^2) : G \mbox{ is a 2-degenerate graph} \} \leq 3 Δ(G) +1}. \] So, it was naturally asked whether there exists a constant $D_0$ such that $χ(G^2) \leq \frac{5}{2} Δ(G)$ if $G$ is a 2-degenerate graph with $Δ(G) \geq D_0$. Recently Cranston and Yu [3] showed that $ω(G^2) \leq \frac{5}{2} Δ(G)+72$ if $G$ is a 2-degenerate graph, and $ω(G^2) \leq \frac{5}{2} Δ(G)+60$ if $G$ is a 2-degenerate graph with $Δ(G) \geq 1729$. We show that there exists a constant $D_0$ such that $ω(G^2) \leq \frac{5}{2} Δ(G)$ if $G$ is a 2-degenerate graph with $Δ(G) \geq D_0$. This upper bound on $ω(G^2)$ is tight by the construction in [6].