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Lines in metric spaces: universal lines counted with mult...
Martín Matamala, José Zamora · 2018-03-20 · via math.CO updates on arXiv.org

The line generated by two distinct points, $x$ and $y$, in a finite metric space $M=(V,d)$, denoted by $\overline{xy}^M$, is the set of points given by $$\overline{xy}^M:=\{z\in V: d(x,y)=|d(x,z)\pm d(z,y)|\}.$$ A 2-set $\{x,y\}$ such that $\overline{xy}^M=V$ is called a universal pair and its associated line a universal line. Chen and Chvátal conjectured that in any finite metric space either there is a universal line or there are at least $|V|$ different (non-universal) lines. Chvátal proved that this is indeed the case when the metric space has distances in the set $\{0,1,2\}$. Aboulker et al. proposed the following strengthening for Chen and Chvátal conjecture in the context of metric spaces induced by finite graphs. The number of lines plus the number of universal pairs is at least the number of point of the space. In this work we first prove that metric spaces with distances in the set $\{0,1,2\}$ satisfy this stronger conjecture. We also prove that for metric spaces induced by bipartite graphs the number of lines plus the number of bridges of the graph is at least the number its vertices, unless the graph is $C_4$ or $K_{2,3}$.