leetcode 869. Reordered Power of 2

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leetcode 869. Reordered Power of 2

司徒正美 · 2020-01-10 · via 博客园 - 司徒正美

function reorderedPowerOf2(N) {
            var a1 = N.toString().split('')
            a1.sort((a, b) =>
                a.localeCompare(b)
            )

            var s1 = a1.join('')

            for (let i = 0; i < 31; i++) {
                var a2 = String(1 << i).split('')
                a2.sort((a, b) =>
                    a.localeCompare(b)
                )
                if (s1 === a2.join(''))
                    return true;
            }

            return false;
        }

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