惯性聚合 高效追踪和阅读你感兴趣的博客、新闻、科技资讯
阅读原文 在惯性聚合中打开

推荐订阅源

Microsoft Azure Blog
Microsoft Azure Blog
WordPress大学
WordPress大学
让小产品的独立变现更简单 - ezindie.com
让小产品的独立变现更简单 - ezindie.com
The Cloudflare Blog
U
Unit 42
D
Docker
Hugging Face - Blog
Hugging Face - Blog
博客园 - 聂微东
Recent Announcements
Recent Announcements
GbyAI
GbyAI
T
The Blog of Author Tim Ferriss
Last Week in AI
Last Week in AI
V
Visual Studio Blog
I
InfoQ
Google DeepMind News
Google DeepMind News
小众软件
小众软件
L
LangChain Blog
C
Check Point Blog
宝玉的分享
宝玉的分享
Martin Fowler
Martin Fowler
酷 壳 – CoolShell
酷 壳 – CoolShell
博客园 - 【当耐特】
J
Java Code Geeks
罗磊的独立博客

博客园 - 司徒正美

leetcode 91. Decode Ways leetcode 1214 Two Sum BSTs leetcode 213 House Robber II leetcode 986. Interval List Intersections leetcode 869. Reordered Power of 2 leetcode 925. Long Pressed Name leetcode 457. Circular Array Loop leetcode 1093. Statistics from a Large Sample leetcode 881. Boats to Save People leetcode 977. Squares of a Sorted Array leetcode 844. Backspace String Compare leetcode 1032. Stream of Characters leetcode 1023. Camelcase Matching leetcode 745 Prefix and Suffix Search leetcode 720. Longest Word in Dictionary leetcode 692. Top K Frequent Words leetcode 677. Map Sum Pairs leetcode 676. Implement Magic Dictionary leetcode 648. Replace Words
leetcode 198 House Robber I
司徒正美 · 2020-01-14 · via 博客园 - 司徒正美
function rob(nums) {
    if(!nums || nums.length === 0) {
        return 0;
    } else if(nums.length < 2){
        return nums[0];
    }
    let memo = new Array(nums.length);
    memo[0] = nums[0];
    memo[1] = Math.max(nums[0], nums[1]);
    for(let i = 2; i < nums.length; i++) {
        memo[i] = Math.max(memo[i-2]+nums[i], memo[i-1]);
    }
    return memo[memo.length-1];
}