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噜啦 - if

django if标签 - 噜啦 for if 嵌套 - 噜啦 条件语句 if判断 - 噜啦
while if 嵌套 - 噜啦
博主: 噜啦 · 2019-09-06 · via 噜啦 - if
  • 发布时间:
  • 1607 次浏览
  • 690字数
  • 分类: Python笔记本
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代码

zodiac_name = (u'摩羯座', u'水瓶座', u'双鱼座', u'白羊座', u'金牛座', u'双子座',
           u'巨蟹座', u'狮子座', u'处女座', u'天秤座', u'天蝎座', u'射手座')
zodiac_days = ((1, 20), (2, 19), (3, 21), (4, 21), (5, 21), (6, 22),
              (7, 23), (8, 23), (9, 23), (10, 23), (11, 23), (12, 23))

# 用户输入月份和日期
int_month = int(input('请输入月份:'))
int_day = int(input('请输入日期:'))

n=0
while zodiac_days[n] < (int_month, int_day):
    if int_month == 12 and int_day > 23:
        break
    n += 1
print(zodiac_name[n])

运行

**注意Python里面的缩进**

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while if 嵌套

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