解决多个异步操作嵌套问题
祈雨的笔记
·
2019-01-07
·
via 祈雨的笔记
JavaScript Promise
用Promise解决多个异步操作嵌套问题
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
| let ansyFun = function(count, wait){ return new Promise((resolve, reject) => { setTimeout(() => { console.log(count, new Date()); resolve(count+1); }, wait); }); }
let promise = new Promise(function(resolve, reject) { resolve(1); });
promise.then(data => { return ansyFun(data, 1000); }).then(data => { return ansyFun(data, 1000); }).then(data => { return ansyFun(data, 2000); });
|
用Promise+async解决多个异步操作嵌套问题
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
| let ansyFun = function(count, wait){ return new Promise((resolve, reject) => { setTimeout(() => { console.log(count, new Date()); resolve(count+1); }, wait); }); }
async function asyncFun(){ let count = 1; count = await ansyFun(count, 1000); count = await ansyFun(count, 1000); count = await ansyFun(count, 2000); } asyncFun();
|
此内容由惯性聚合(RSS阅读器)自动聚合整理,仅供阅读参考。 原文来自 — 版权归原作者所有。