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Jiajun的技术笔记

你好,2026! TiDB 源码阅读(六):TiDB Coprocessor 源码解析 性能优化的核心思想 TiDB 源码阅读(五):索引 TiDB 源码阅读(四):AST、逻辑计划、物理计划 CockroachDB Serverless Architecture podman 无故退出 Cursor Control-L (CTRL-L) Keyboard Shortcuts in Terminal Replace docker with podman Using xmonad with xfce4 A RC script for freebsd frpc 自己动手写一个k8s controller AI 会取代你的(编程)岗位吗? 自建DERP服务器提升Tailscale连接速度(使用Nginx转发) 自动升级Docker容器 再读《程序员修炼之道-从小工到专家》 让浏览器下载文件 再读《软件随想录》/《黑客与画家》/《软技能》 HTTP 压力测试中的 Coordinated Omission 2的补码 编程语言中的 context 是什么? flutter macOS 构建出错 Flatpak 使用小记 Golang CAS 操作是怎么实现的 PostgreSQL 当MQ来使用 Clash 结合 工作VPN 的网络设计 使用 PostgreSQL 搭建 JuiceFS PostgreSQL 配置优化和日志分析 有GitHub Copilot?那就可以搭建你的ChatGPT4服务 窗口函数的使用(以PG为例)
How to implement fork syscall in Golang?
Jiajun Huang · 2018-08-28 · via Jiajun的技术笔记

中文版

ref: https://github.com/moby/moby/tree/master/pkg/reexec

We don’t have a fork syscall in Golang, we have:

All those three functions is like a combination of fork + exec, but there has no pure fork syscall just like in C programming language(after syscall, which will return pid in caller). Reasons can be found in here:

It mainly says:

  • fork() has been invented at the time when no threads were used at all, and a process had always had just a single thread of execution in it, and hence forking it was safe.
  • In C, you control all the threads by your hand, but in Go, you cannot, so threads will be out of control after call fork without exec, so Go provides fork + exec only.

Let’s have a look at how we use pure fork in C:

#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include <sys/wait.h>

void child() {
    printf("child process\n");
}

int main() {
    printf("main process\n");
    pid_t pid = fork();
    int wstatus;

    if (pid == 0) {
        child();
    } else {
        printf("main exit\n");
        waitpid(pid, &wstatus, 0);
    }
}

Run it:

$ gcc main.c && ./a.out
main process
main exit
child process

Let’s look how can we implements this in Go:

package main

import (
	"log"
	"os"

	"github.com/docker/docker/pkg/reexec"
)

func init() {
	log.Printf("init start, os.Args = %+v\n", os.Args)
	reexec.Register("childProcess", childProcess)
	if reexec.Init() {
		os.Exit(0)
	}
}

func childProcess() {
	log.Println("childProcess")
}

func main() {
	log.Printf("main start, os.Args = %+v\n", os.Args)
	cmd := reexec.Command("childProcess")
	cmd.Stdin = os.Stdin
	cmd.Stdout = os.Stdout
	cmd.Stderr = os.Stderr
	if err := cmd.Start(); err != nil {
		log.Panicf("failed to run command: %s", err)
	}
	if err := cmd.Wait(); err != nil {
		log.Panicf("failed to wait command: %s", err)
	}
	log.Println("main exit")
}

Run it:

$ go run main.go
2018/03/08 19:52:39 init start, os.Args = [/tmp/go-build209640177/b001/exe/main]
2018/03/08 19:52:39 main start, os.Args = [/tmp/go-build209640177/b001/exe/main]
2018/03/08 19:52:39 init start, os.Args = [childProcess]
2018/03/08 19:52:39 childProcess
2018/03/08 19:52:39 main exit

Explanation:

init will be execute before main function. When you execute the binary executable file from command line, os.Args[0] will be the name of binary executable file, but, reexec.Command will change os.Args[0], so child process will find function registed by reexec.Register, and execute it, return true, then call os.Exit(0).


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