echo '1 2'|awk "{print $2}"的输出为什么是 1 2 - V2EX
freemoon
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2020-03-22
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via Bash
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3
ynyounuo 2020 年 3 月 22 日
> Double quotes protect most things between the opening and closing quotes. The shell does at least variable and command substitution on the quoted text. Different shells may do additional kinds of processing on double-quoted text.
> Because certain characters within double-quoted text are processed by the shell, they must be escaped within the text. Of note are the characters ‘$’, ‘`’, ‘\’, and ‘"’, all of which must be preceded by a backslash within double-quoted text if they are to be passed on literally to the program.
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