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js parseInt与排序
.net小鸟 · 2011-11-04 · via 博客园 - .net小鸟

js的三个常见问题
<script>
  //1.parseInt,在使用parseInt的时候,如果不指定第二个参数,而转换0123这种类型的字符串的时候就会按照八进制转成整形
  var oInt = "0012";
  alert(parseInt(oInt));
  //正确的是
  alert(parseInt(oInt,10));
  //2.排序问题
  var intArr=[1,4,2,5,10,3,21]
  intArr.sort()
  var temp="";
  for(var i=0;i<intArr.length;i++){
 temp+=intArr[i]+",";
  }
  alert(temp);//弹出,1,10,2,21,3,4,5,
  //正确的方法是写个匿名函数
  intArr.sort(function(a,b){//a-b是asc,b-a是desc,如果a,b是对象的话可以,用a.xx-b.xx
 return a-b;
  })
  var temp1="";
  for(var i=0;i<intArr.length;i++){
 temp1+=intArr[i]+",";
  }
  alert(temp1)//输出正常
 
 
</script>

posted on 2011-11-04 16:53  .net小鸟  阅读(327)  评论()    收藏  举报