相信有不少人使用过这样的转换函数，也许还有人在寻找呢，毕竟用的地方比较多，这里就提供一个javascript版的转换函数。还有一个 SQL 存储过程版本的（SQL版）
（已经记不得是在哪儿 copy 来的了．．．）

// JScript 文件

//限制输入数字及小数点
function regInput(reg)
{
var srcElem = event.srcElement
var oSel = document.selection.createRange()
oSel = oSel.duplicate()
oSel.text = ""
var srcRange = srcElem.createTextRange()
oSel.setEndPoint("StartToStart", srcRange)
var num = oSel.text + String.fromCharCode(event.keyCode) + srcRange.text.substr(oSel.text.length)
event.returnValue = reg.test(num)
}

//转换为中文大写
function chineseNumber(num)
{
if (isNaN(num) || num > Math.pow(10, 12)) return ""
var cn = "零壹贰叁肆伍陆柒捌玖"
var unit = new Array("拾佰仟", "分角")
var unit1= new Array("万亿", "")
var numArray = num.toString().split(".")
var start = new Array(numArray[0].length-1, 2)

function toChinese(num, index)
{
var num = num.replace(/\d/g, function ($1)
{
return cn.charAt($1)+unit[index].charAt(start--%4 ? start%4 : -1)
})
return num
}

for (var i=0; i<numArray.length; i++)
{
var tmp = ""
for (var j=0; j*4<numArray[i].length; j++)
{
var strIndex = numArray[i].length-(j+1)*4
var str = numArray[i].substring(strIndex, strIndex+4)
var start = i ? 2 : str.length-1
var tmp1 = toChinese(str, i)
tmp1 = tmp1.replace(/(零.)+/g, "零").replace(/零+$/, "")
tmp1 = tmp1.replace(/^壹拾/, "拾")
tmp = (tmp1+unit1[i].charAt(j-1)) + tmp
}
numArray[i] = tmp
}

numArray[1] = numArray[1] ? numArray[1] : ""
numArray[0] = numArray[0] ? numArray[0]+"圆" : numArray[0], numArray[1] = numArray[1].replace(/^零+/, "")
numArray[1] = numArray[1].match(/分/) ? numArray[1] : numArray[1]+"整"
return numArray[0]+numArray[1]
}

//转换为小写
function aNumber(num)
{
var numArray = new Array()
var unit = "亿万圆$"
for (var i=0; i<unit.length; i++)
{
var re = eval("/"+ (numArray[i-1] ? unit.charAt(i-1) : "") +"(.*)"+unit.charAt(i)+"/")
if (num.match(re))
{
numArray[i] = num.match(re)[1].replace(/^拾/, "壹拾")
numArray[i] = numArray[i].replace(/[零壹贰叁肆伍陆柒捌玖]/g, function ($1)
{
return "零壹贰叁肆伍陆柒捌玖".indexOf($1)
})
numArray[i] = numArray[i].replace(/[分角拾佰仟]/g, function ($1)
{
return "*"+Math.pow(10, "分角 拾佰仟 ".indexOf($1)-2)+"+"
}).replace(/^\*|\+$/g, "").replace(/整/, "0")
numArray[i] = "(" + numArray[i] + ")*"+Math.ceil(Math.pow(10, (2-i)*4))
}
else numArray[i] = 0
}
return eval(numArray.join("+"))
}
//JS结束
-----------------------------------
使用方法：
         onblur="document.getElementById('id').value=chineseNumber(this.value)"

限制输入数字及小数点的 regInput:
         onkeypress="regInput(/^\d{0,12}(\.\d{0,2})?$/)"